The sum of all two digit numbers greater than 60 which when divided by 7 leaves a remainder 4 is
Answers
Answered by
0
Answer:
Mark me as brainliests..
Attachments:
Answered by
0
Answer:
The number should be the form 7n+4
Should be 50<7n+4<100
∴ Numbers are 53,60,…..95
a=53
d=7
n
th
term =a+(n−1)d
⇒53+(n−1)7=95
⇒(n−1)
7=
42
6
⇒n=7
S
n
=
2
n
(2a+(n−1)d)
=
2
7
(2×53+(7−1)7)
=
2
7
[106+42]
=518.
Step-by-step explanation:
plz mark as brainliest
Similar questions