Question

The sum of all two digits even numbers is
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Answer 1

Step-by-step explanation:

a = 10 ; d = 2 ; l = 98

l = a + (n-1) d

98 = 10 + ( n - 1) 2

n - 1 = 88/2

n = 45

sum = n/2 (2a + ( n - 1 ) d)

      = 45/2 ( 2*10 + 88/2 * 2)

      = 45/2 ( 20 + 88)

      = 45/2 * 108

      = 2430

Answer 2

Answer:

10+12+14+16+18+20+22+24+26+28+30+32+34+36+38+40+42+44+46+48+50+52+54+56+58+60+62+64+66+68+70+72+74+76+78+80+82+84+86+88+90+92+94+96+98=2430

Step-by-step explanation:

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