Question

The sum of all two digits numbers divisible by 11 is


495


945


568


678

Answer 1

Answer:

495

Step-by-step explanation:

495is exactly divisible by 11

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Answer 2

The sum of all two digits numbers divisible by 11 by 495.

GIVEN

Dividend = 2 digit numbers

Divisor = 11

TO FIND

Sum of all 2-digit number divisible by 11.

SOLUTION

We can simply solve the above problem as follows;

We know that, 2-digit numbers start from 10 to 99.

2-digit Numbers exactly divisible by 11 are, 11, 22,33,44,55,66,77,88, and 99.

The above number series form an A.P

Number of 2-digit number = 9.

Sum of 9 terms of AP = s = n/2 [2a + (n − 1) × d]

Where,

a = First term

n = last term of the series

d = common difference.

Putting the values in the above formula we get,

$s = \frac{9}{2} [2 \times 11 +(9 - 1) \times 11 ]$

= 495

Hence, The sum of all two digits numbers divisible by 11 by 495.

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