The sum of an airthametic series with 15 terms is 180 then the 8th term is
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Answered by
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The formula for the sum of an arithmetic series is:
S = (n/2)(1st + last)
where n = the number of terms = 15
1st = 1st term = x
last = last term = x + (n-1)(d)
180 = (15/2)(x + x + 14d)
180 = (15/2)(2x + 14d)
360/15 = 2x + 14d
24 = 2x + 14d
12 = x + 7d
8th term = x + (8-1)d
8th term = x + 7d
as you can see, simplifying the sum of the series gave us that x + 7d was 12, therefore the 8th term is 12
S = (n/2)(1st + last)
where n = the number of terms = 15
1st = 1st term = x
last = last term = x + (n-1)(d)
180 = (15/2)(x + x + 14d)
180 = (15/2)(2x + 14d)
360/15 = 2x + 14d
24 = 2x + 14d
12 = x + 7d
8th term = x + (8-1)d
8th term = x + 7d
as you can see, simplifying the sum of the series gave us that x + 7d was 12, therefore the 8th term is 12
Answered by
3
Answer:
hiiii
Step-by-step explanation:
The formula for the sum of an arithmetic series is:
S = (n/2)(1st + last)
where n = the number of terms = 15
1st = 1st term = x
last = last term = x + (n-1)(d)
180 = (15/2)(x + x + 14d)
180 = (15/2)(2x + 14d)
360/15 = 2x + 14d
24 = 2x + 14d
12 = x + 7d
8th term = x + (8-1)d
8th term = x + 7d
as you can see, simplifying the sum of the series gave us that x + 7d was 12, therefore the 8th term is 12
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