Math, asked by Zshan9060, 6 months ago

The sum of an infinite G.P. whose
common ratio is positive and is
(Q:6) numerically less than 1 is 36 and the sum
of the first two terms is 32. What will be
the third term?
A.
1/3
B.
4/3
C.
8/3
D.
2.​

Answers

Answered by shakirariyaz6
0

sorry nhi aata hai sorry nahi aata h

Answered by dharan02001
0

Answer:

Step-by-step explanation:

a+ar=32

a(1+r)=32---------1

a/(1-r)=36---------2

from 1 & 2

r=1/3

sub r in 1

a=24

then ar^2 = 8/3

which is the third term

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