Question

the sum of an integer and twice the next integer is 41 . find the integers . any one who will answer step by step correctly will be marked as brillianist . ​

Answer 1

Answer:

First integer is  =13

And, second is =14

Step-by-step explanation:

Let ,first integer be x

 So, second integer is x+1

According to question,

x+2(x+1)=41

 ⟹3x+2=41

 ⟹x=13

Hence,

First integer (x)   =13

second integer = x+1 = 13+1 =14

HOPE IT HELPS ! SATY SAFE ! WEAR MASK !

ALL THE BEST !