Question

the sum of an integer and twice the next integers is 41 find the two integer​

Answer 1

Given,

The sum of an integer and twice the next integers is $41$

We have to find the two integers

Let, the integer be $x$

Twice the next integers is $2(x+1)$

According to the question,

The sum of an integer and twice the next integers is $41$

So,

$x+2(x+1)=41$

$x+2x+2=41$

$3x+2=41$

$3x= 41-2$

$3x=39$

$x= \frac{39}{3}$

$x=13$

And, substitute $x=13$ in the next integer

$2(x+1)= 2(13+1)$

$= 2(14)$

$=48$

Therefore, the two numbers be $13$ and $48$.

Answer 2

As per the data given in the question,

We have to determine the value of integers.

From the data,

It is given that,

The sum of an integer and twice the next integers is 41  

Let, the integer be x

Twice the next integers will be 2(x+1)

So, According to the question,

The sum of an integer and twice the next integers is 41

So, we can conclude it as,

$x+2(x+1)=41\\x+2x+2=41\\3x+2=41\\3x= 41-2\\3x=39\\x= \frac{39}{3}\\x=13\\And,\: substitute\: x=13 \:in \:the\: next\: integer\\2(x+1)= 2(13+1)\\= 2(14)\\=28$

Therefore, the two numbers be 13 and 14.