Question

the sum of an interger and twice the next interger 41 .find the two intergers​

Answer 1

${\boxed{\boxed{\red{\mathcal{ANSWER:}}}}}$

• Two integers are 13 and 14.

Given:

• Sum of an integer and twice of next integer = 41

To Find:

• Two integers.

${\boxed{\boxed{\red{\mathcal{SOLUTION:}}}}}$

Let two Integers are 'x' and 'x + 1'.

According to Question,

$\implies$ x + 2(x + 1) = 41

$\implies$ x + 2x + 2 = 41

$\implies$ 3x = 41 - 2

$\implies$ 3x = 39

$\implies$ x = 39/3

$\implies$ x = 13

So, Two Integers are:

• x = 13
• x + 1 = 13 + 1 = 14

Verification:

• Sum of integer and twice of next integer = 41

$\implies$ 13 + 2(14) = 41

$\implies$ 13 + 28 = 41

$\implies$ 41 = 41

Hence Proved!!

Answer 2

Answer:

refer to the attachment above for ur answer

Step-by-step explanation:

hope it helps you ^_^

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