Question

The sum of an intergerand twice a next integer an d is 41. find the number​

Answer 1

Let ,first integar be x

So, second integer is x+1

According to question,

x+2(x+1)=41

⟹3x+2=41

⟹x=13

Hence,

First integer is =13

And, second is =14

I hope it helps u