the sum of an terms of an AP is 2n²-n-1. Find an!
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sum of first 1 terms is 0
let a be the first term common difference=d
sum of first 2 terms is 5
so we get 2 equations
a=0
a+d=5
so d=5
and nth term=a+(n-1)d
=0+(n-1)5
=5n-5
adityagodara03:
can you explain why you chose sum of 2 terms as 5
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