Question

The sum of angles of a polygon is 9000. How many sides does it have ?​

Answer 1

Answer:

sum of interior angles of polygon = 180° * (the number of sides - 2)

Step-by-step explanation:

We know the sum of the interior angles = 9000°

And let the number of sides = n

9000° = 180° * (n - 2)

Divide both sides of the equation by 180°

9000° / 180° = n - 2

50 = n - 2

Add 2 to both sides of the equation.

52 = n

the number of sides = 52

Hope it helps you

Thank You

Please Mark it as Brainlist

Answer 2

Answer:

$sum of interior angles of polygon = 180° * (the number of sides - 2)</p><p></p><p> </p><p></p><p>We know the sum of the interior angles = 9000°</p><p></p><p>And let the number of sides = n</p><p></p><p> </p><p></p><p>9000° = 180° * (n - 2)</p><p></p><p> Divide both sides of the equation by 180°</p><p></p><p>9000° / 180° = n - 2</p><p></p><p> </p><p></p><p>50 = n - 2</p><p></p><p> Add 2 to both sides of the equation.</p><p></p><p>52 = n</p><p></p><p> </p><p></p><p>n = 52</p><p></p><p> </p><p></p><p>the number of sides = 52$

sum of interior angles of polygon = 180° * (the number of sides - 2)

We know the sum of the interior angles = 9000°

And let the number of sides = n

9000° = 180° * (n - 2)

Divide both sides of the equation by 180°

9000° / 180° = n - 2

50 = n - 2

Add 2 to both sides of the equation.

52 = n

n = 52

the number of sides = 52