Question

The sum of angles of n–sided positive _____________​

Answer 1

Step-by-step explanation:

The sum of the interior angles of a polygon of n sides is equal to (2n - 4) right angles. Given: Let PQRS .... Z be a polygon of n sides.

Answer 2

Answer:

hope it's help you

Step-by-step explanation:

An interior angle of (n + 1) sided regular polygon =

(n+1)

180

o

((n+1)−2)

An interior angle of n sided regular polygon =

n

180

o

(n−2)

Their difference is 4

o

So,

(n+1)

180

o

((n+1)−2)

−

n

180

o

(n−2)

=4

o

=>45[

(n+1)

(n−1)

−

n

(n−2)

]=1

=>45

n(n+1)

2

=1

=>n

2

+n−90=0

=>(n−9)(n+10)=0

=>n=9,−10

Since n should be a positive number. So, n=9