the sum of any two side off triangle is then the third side is
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Step-by-step explanation:
Let ABC be a triangle,
We can extend BA past A into a straight line,
Then there is a point D such that DA=CA
Therefore, from Isosceles triangle has two equal angles,
∠ADC=∠ACD
Thus, in △DCB,
∠BCD>∠BDC (Side opposite greater angle is larger)
Thus, BD>CD
BA+AD>CD (Since, AC=AD)
BA+AC>CD
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