Question

The sum of area of the squares of side 2 a and 2 b is

Answer 1

Step-by-step explanation:

area of the squares of side 2 a equals (2a)^2 = 4 a².

area of the squares of side 2 b equals (2b)^2 =

their sum =4a²+4 b²

=4(a²+b²)

Answer 2

Answer:

Let the sides of the two squares be of a and b.

The according to the problem

a  2 +b  2  =640.........(1).

Again 4(a−b)=64

or, a−b=16.......(2).

Using (2) in (1) we get,

a  2  +(−16+a)  2 =640 or, 2a  2

−32a+256=640

or, 2a  2  −32a−384=0 or, a  2  −16a−192=0

or, (a−24)(a+8)=0

Since a is the side of a square then a=24⇒b=8.

So the sides of the squares be 24 m and 8 m.

Step-by-step explanation: