the sum of area of two spure is 400m cube and there perimeter difference is 16m Find length of each square.
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let side of first square=x
let side of second square=y
as we know perimeter of square is 4s so now a/q
4x-4y= 16
4(x-y)=4×4
x-y=4
x=4+y
now
y^2+(4+y)^2=400
y^2+16+y^2+8y=400
2y^2+16+8y=400
y^2+8+4y=200
y^2+4y-192=0
after evaluation
y=12 and x=12+4=16
so sides are 12m and 16m
let side of second square=y
as we know perimeter of square is 4s so now a/q
4x-4y= 16
4(x-y)=4×4
x-y=4
x=4+y
now
y^2+(4+y)^2=400
y^2+16+y^2+8y=400
2y^2+16+8y=400
y^2+8+4y=200
y^2+4y-192=0
after evaluation
y=12 and x=12+4=16
so sides are 12m and 16m
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