Question

the sum of areas of 2squares is 640m^2 if the difference between their perimeter is 64 m then find sides of the square​

Answer 1

Answer:

let sides of square be x and y ,

x² + y² = 640

4x-4y = 64

(x-y) = 16 ----------------(1)

Now,we know that,(x-y)² = x²+y²-2xy

put values ,

256 = 640 - 2xy

2xy = 384

xy = 192

again, (x+y)² = (x-y)²+4xy

(x+y)² = 256+4*192 = 1024

(x+y) = 32 --------------------- (2)

solving (1) and (2) we get,

x = 24, y = 8 (ans.)

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