Question

The sum of areas of two sqares is 468cm×cm. If the sum of their perimeters is 120cm,then the difference of their sides is

Answer 1

a1+a2= 468    =>s12+s22=468

4(s1+s2)=120

s1+s2=30----(1)

squaring on both sides

s12+s22+2s1s2=900

2s1s2=900-468=432

(s1-s2)2=s12+s22-2s1s2

           = 468-432

           = 36

s1-s2= root 36

s1-s2=6