Question

the sum of areas of two square is 640 m square. if the difference of their perimeter is 64 m . find the side of two square ​

Answer 1

Answer:

let side of first square be x

let side of second square be y

now

x^2+y^2=640------------(1)

then. 4x-4y=64

4(x-y)=64

x=16+y

put x in (1)

(16+y)^2+y^2=640

256+y^2+32y+y^2=640

(256-640)+2y^2+32y=0

-384+2y^2+32y=0

2y^2+32y-384=0

dividing by 2

y^2+16y-192=0

y^2+24y-8y-192=0

y(y+24)-8(y+24)=0

(y-8)(y+24)=0

y=8

y=24(side can neither be negative)

x=16+y=16+8=24

hence side of one square is y= 8

and another is x=24