Question

The sum of areas of two squares is 400sq.m.If the difference between their perimeters is 16 then find the sides of two
squares

Answer 1

Answer:48 m,52 m

Step-by-step explanation:

Difference in sides=16/4

=4 m

Let the sides be x m and (x+4) m.

A.T.Q

(x+4)²-(x)²=400 m²

x²+8x+16-x²=400

8x=384

x=48 m

Sides=48 m

52 m

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