Question

The sum of areas of two squares is 640 difference of their perimeter is 64 find the side of a square. ​

Answer 1

Step-by-step explanation:

let the side of one square be X

perimeter of the square=4x

difference between the two squares = 64

perimeter of 1 square= 64+4x

perimeter of 2 square 64+4x/4 = (16+X)

x^2+(16+X)^2= 640

x^2+256+32x+ x^2= 640

2x^2+32x-384=0

x^2+16x-192=0

x(X+24)-8(X+24)=0

(x+24)(x-8)

x=24,8

Answer 2

Answer:

Refers to the attachment