Question

the sum of areas of two squares is 73 metre square the side of square is 5 more than the other find the sides of the squares​

Answer 1

Answer:

So, the side of square is 3 and 8.

Step-by-step explanation:

GIVEN :

.

Sum of the areas of two squares =73 m²

Let the side of one of the square be x m.

so, area of the square = x²

the side of other square will be ( x + 5 ) m.

so, the area of the square = ( x + 5 )²

So, sum of areas of both square will be

x² + ( x + 5 )² which is equal to 73 m²

so, x² + x² + 25 + 10x = 73

or, 2x² + 10x - 48 = 0

or, 2x² + 16x - 6x - 48 = 0

so, ( x + 8 )( 2x - 6 ) = 0

so, x = - 8 or 3.

neglect negative values .

So, the side of square is 3 and 8.

Answer 2

$\huge\mathfrak\blue{Answer:}$

Given:

The sum of areas of two squares is 73 metre square the side of square is 5 more than the other

To Find:

The sides of the squares

Solution:

Let us assume that the length of side of one square is = x cm

According to the question, length of side of other square is = x + 5

Area of first square = ( x ) ( x) = x^2

Area of second square = ( x + 5 ) ( x+ 5)

By Question:

sum of area two squares = 73 sq m

x^2 +  ( x + 5)^2 = 73

x^2 + x^2 + 10x + 25 -73 =0

x^2 +10 x -48 = 0

By factorizing we get

( x - 3 ) ( x + 8 ) =0

Therefore, either x = 3 or  x=-8

Since the value of length of square cannot be negative, so x = 3.

Hence, the length of side of one square is  x = 3 and length of side other square = x + 5 = 3 + 5 = 8.