Question

The sum of areas of two squares is 73m^2.The side of one square is 5m more than the other square.Find the sides of both the squares​

Answer 1

Answer:

let the length of side of one square is = x cm

let the length of side of other square is = x + 5 ( as given condition )

the Area of first square = ( x ) ( x) = x^2

the Area of second square = ( x + 5 ) ( x+ 5)

given condition :

sum of area two square will = 73 sqr.

  x^2 +  ( x + 5)^2 = 73

x^2 + x^2 + 10x + 25 -73 =0

x^2 +10 x -48 = 0

by factorizing we get

( x - 3 ) ( x + 8 ) =0

so either x = 3 or  x=-8 ( -ve value discarded )

so the length of side of one square is  x = 3 and other square will be

x = 3+5 => 8

Proof:

( 3^2 ) + ( 8^2) = 9 + 64 = 73 ( proved )

Step-by-step explanation:

Answer 2

let the side of one square be x

according to question

x²+(x+5)²=73

x²+x²+25+10x=73

2x²+10x=73-25=48

x²+5x-24=0

x²+8x-3x-24=0

x(x+8)-3(x+8)=0

x=-8 or 3

sides of squares are 1st square=3m

2nd square=5+3=8m