Question

the sum of Arithmetic progression 2+4+6+8………to 20 terms is​

Answer 1

Answer: 240

Step-by-step explanation:

a = 2

d = 4-2

= 2

l = 2 + 19(2) [a + (n-1)d]

= 2 + 38

= 40

S = n/2 * (a + l)

= 20/2 * (2+40)

= 10 * 24

= 240.

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Answer 2

Answer:

$= >$

Ap = 2,4,6,.......... 20

a(first term) = 2

n=20 (nth term)

d(common difference) = t2-t1=4-2=2

therefor,

Sn (sum of all terms)

= n/2 x ( 2a+(n-1)d)

=20/2 x (2x2+(20-1)2)

=10 x (4+19x2)

=10 x (4+38)

=420•