The sum of Arithmetic progression 4+12+20+.....+100 is
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The sum of Arithmetic progression 4+12+20+.....+100 is 676
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Q) The sum of Arithmetic progression 4+12+20+.....+100 is
⇒ given, arithmetic progression is 4,12,20,.....,100
the arithmetic nth term is obtained by adding 8 in (n-1)th term
∴ the arithmetic progression is 4,12,20,28,36,44,52,60,68,76,84,92,100
The sum of Arithmetic progression 4+12+20+.....+100 is -
∴ 4+12+20+.....+100 = 4+12+20+28+36+44+52+60+68+76+84+92+100
∴ 4+12+20+.....+100 = 676
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find the sum of 4+12+20+_ _ _ _ _ +100
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