Question

the sum of bhavana's present age and her age after 10 years is 42. find her present age​

Answer 1

Supposition

let her age be X.

and her age after 10years be X+10

according to the question:-

X+X+10 = 42

2x+10 = 42

2x = 32

X = $\sf\cancel\dfrac{32}{2}$ = 16

hence, her present age is 16 years

Answer 2

Solution :

Here, given that sum of Bhavana's present age and her age after 10 years is 42.

Steps :

The present age of Bhavana is not given. So, let her present age be k years and after 10 years her age will be (k + 10) years.

• Present age of Bhavana = k years
• After, 10 years Bhavana's age = (k + 10) years

Sum of present age of Bhavana and after 10 years Bhavana's age is 42.

We've to find her present age.

Now, according to question :

➥ k + (k + 10) = 42

➥ k + k + 10 = 42

➥ 2k + 10 = 42

➥ 2k = 42 - 10

➥ 2k = 32

➥ k = 32/2

➥ k = 16 years

• Hence, the present age of Bhavana is 16 years.