the sum of circumference of four small circles of equal radius is equal to the circumference of a bigger circle find the ratio of the area of the bigger Circle to that of the smaller circle
Answers
Answered by
5
let radius of smaller circles be r and that of big circle be R
acc to ques
(2pie r^2)×4=2 pir R^2
8pirr^2=2pieR^2
r^2 =R^2/4
r=R/2---------1
area of big circle /area of small circle
pieR^2/pier^2
(R/r)^2
(R/R/2)^2
4:1
acc to ques
(2pie r^2)×4=2 pir R^2
8pirr^2=2pieR^2
r^2 =R^2/4
r=R/2---------1
area of big circle /area of small circle
pieR^2/pier^2
(R/r)^2
(R/R/2)^2
4:1
Answered by
17
Hey there!
4 Circles (small) have radius = r
Circle's (big) radius = R
Circumference of circle is = 2πr
ATQ,
4 × 2πr = 2πR
R = 4r
So, R/r = 4 -----(1)
Area = area of Bigger circle/area of Small circle
= (R/r)²(R/r)²
(Using eqn. 1)
= 4 × 4 : 1
= 16 : 1
Hence,
The required ratio is 16:1
HOPE IT HELPED ^_^
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