Math, asked by armaankudrat, 10 months ago

the sum of circumferences of four small circles of equal radius is equal to the circumference of a bigger circle.Find the ratio of the bigger circle of that of smaller circle​

Answers

Answered by BrainlyConqueror0901
33

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\therefore{\text{Ratio\:of\:radius=4:1}}}

\green{\therefore{\text{Ratio\:of\:Area=16:1}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{ \underline \bold{Given : }} \\   : \implies  \text{Small \:circle \:  radius = r} \\  \\   : \implies  \text{Big \: circle \: radius = R} \\  \\   : \implies   \text{Circumference \: of \: four \: circle = Circumference \: of \: big \: circle} \\  \\ \red{ \underline \bold{To \: Find : }} \\  :  \implies  \text{Ratio \: of }\:  \:  \:  \frac{R}{r}  = ?

• In the given question information given about the sum of circumferences of four small circles of equal radius is equal to the circumference of a bigger circle and we have to find the ratio of the bigger circle of that of smaller circle.

• According to given question :

 : \implies \text{Circumference \:of \: small \: circle = }2\pi \: r \\  \\   : \implies  \text{Circumference \: of \: 4 \: small \: circle = 4 }\times \pi \: r \\ \\  \bold{Again,}  \\  :  \implies Circumference \: of \: big \: circle = 2\pi \: R \\  \\   : \implies 8\pi r = 2\pi \: R\\  \\  :   \implies  \frac{8\pi r}{2\pi }  = R \\  \\   : \implies R  = 4r \\   \\  \bold{For \: Ratio \: of \: their \: radii}\\   : \implies Ratio  \: of \: their \: radi =  \frac{Big \: circle }{Small \: circle}  \\  \\    \green{:  \implies  Ratio =  \frac{R}{r}   =  \frac{4r}{r}   =  \frac{4}{1} } \\   \\  \bold{For \: Ratio \: of \: their \: area's}\\   : \implies Ratio \: of \: their \: area =  \frac{Area \: of \: big \: circle}{Area \: of \: small \: circle}   \\  \\    :\implies Ratio =  \frac{\pi {R}^{2} }{\pi {r}^{2} }  \\  \\    :  \implies  Ratio =  \frac{ {4r}^{2} }{ {r}^{2} }  \\  \\    \green{: \implies Ratio =  \frac{16r}{r}   =  \frac{16}{1} }

Answered by RvChaudharY50
88

Correct Question :--- the sum of circumferences of four small circles of equal radius is equal to the circumference of a bigger circle.Find the ratio of the area bigger circle of that of area of one smaller circle.. ?

Concept And Formula :---

→ Circumference of a circle with radius r is given by 2πr ..

→ Area of a circle with radius r is given by πr².

→ Ratio of Circumference of 2 circle with Radius as r1 and r2 is given by = r1:r2.

→ Ratio of Area of 2 circle with Radius as r1 and r2 is given by = (r1)² : (r2)²

[ Reason :-- As π will cancel From both sides we get, only Radius Result in Ratios. ]

__________________________

Solution :---

Let radius of Each smaller circle be = r

and, radius of big circle be = R.

According to Question Now,

→ Circumference of one Small circle = 2πr

→ Circumference of 4 Small circle = 4*2πr = 8πr .

So,

Circumference of Big circle = Circumference of 4 Small circle

→ Circumference of Big circle = 8πr

→ 2πR = 8πr

Dividing both sides by 2π we get,

→ R = 4r .

_________________________

Now, Either we put This value in Formula of Area for Required ratio, or we can simply , Square the ratios .

Lets Try both :---

Area of one smaller circles = πr²

→ Area of big circle = π(R²)

Putting value of R = 4r now, we get,

→ Area of big circle = π(4r)² = 16πr²

So,

Required ratio =

Area of big circle : Area of one small circles = 16πr² : πr²

16πr² : πr²

Dividing both sides by πr² we get

→ 16 : 1 (Ans.)

____________________

Now, lets see it by above told concept .

Area Ratio = (r1)² : (r2)²

→ smaller circle radius = r

→ bigger circle radius = R

And,

R = 4r

so,

→ Area of big circle : Area of one small circles = (R)² : (r)²

Putting value ,

Area of big circle : Area of one small circles = (4r)² : r²

→ Area of big circle : Area of one small circles = 16r² : r²

→ Area of big circle : Area of one small circles = 16 : 1

__________________________

Hence, ratio of Area of bigger circle to one smaller circle will be 16:1 ..

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