the sum of circumferences of four small circles of equal radius is equal to the circumference of a bigger circle.Find the ratio of the bigger circle of that of smaller circle
Answers
• In the given question information given about the sum of circumferences of four small circles of equal radius is equal to the circumference of a bigger circle and we have to find the ratio of the bigger circle of that of smaller circle.
• According to given question :
Correct Question :--- the sum of circumferences of four small circles of equal radius is equal to the circumference of a bigger circle.Find the ratio of the area bigger circle of that of area of one smaller circle.. ?
Concept And Formula :---
→ Circumference of a circle with radius r is given by 2πr ..
→ Area of a circle with radius r is given by πr².
→ Ratio of Circumference of 2 circle with Radius as r1 and r2 is given by = r1:r2.
→ Ratio of Area of 2 circle with Radius as r1 and r2 is given by = (r1)² : (r2)²
[ Reason :-- As π will cancel From both sides we get, only Radius Result in Ratios. ]
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Solution :---
Let radius of Each smaller circle be = r
and, radius of big circle be = R.
According to Question Now,
→ Circumference of one Small circle = 2πr
→ Circumference of 4 Small circle = 4*2πr = 8πr .
So,
→ Circumference of Big circle = Circumference of 4 Small circle
→ Circumference of Big circle = 8πr
→ 2πR = 8πr
Dividing both sides by 2π we get,
→ R = 4r .
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Now, Either we put This value in Formula of Area for Required ratio, or we can simply , Square the ratios .
Lets Try both :---
→ Area of one smaller circles = πr²
→ Area of big circle = π(R²)
Putting value of R = 4r now, we get,
→ Area of big circle = π(4r)² = 16πr²
So,
Required ratio =
Area of big circle : Area of one small circles = 16πr² : πr²
→ 16πr² : πr²
Dividing both sides by πr² we get
→ 16 : 1 (Ans.)
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Now, lets see it by above told concept .
Area Ratio = (r1)² : (r2)²
→ smaller circle radius = r
→ bigger circle radius = R
And,
→ R = 4r
so,
→ Area of big circle : Area of one small circles = (R)² : (r)²
Putting value ,
→ Area of big circle : Area of one small circles = (4r)² : r²
→ Area of big circle : Area of one small circles = 16r² : r²
→ Area of big circle : Area of one small circles = 16 : 1