The sum of circumferences of four small circles of equal radius is equal to the
circumference of a bigger circle. Find the ratio of the area of the bigger circle to that o
the smaller circle.
Answers
Answered by
4
Answer:
16 : 1
Step-by-step explanation:
Let the radius of small circles be r and that of big circle be R.
Circumference of each small circle = 2πr, since small circles have same radius their circumference is equal.
Circumference of big circle = 2πR.
Here, sum of circumferences of four small circles of equal radius is equal to the
circumference of a bigger circle, which means,
=> 2πr + 2πr + 2πr + 2πr = 2πR
=> 8πr = 2πR
=> 4r = R
Ratio of area of bigger to smaller circle:
=> area(big) ; area(small)
=> (πR²) / (πr²)
=> R² / r² , note that 4r = R
=> (4r)² / r²
=> 16r²/r²
=> 16
Answered by
2
Answer:
circumference =3 area
2πr = 3π r^2
2r = 3r^2
2= 3r
3/2= r
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