The sum of coefficient in the expansion of (x+1)⁵
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Answer:
Step-by-step explanation:
In bionomial expansion of (a+b)^n, n is a positive integer the sum of odd coefficients equal 2^n-1
So for (1+x)^5,sum of odd coefficients will be:
2^5-1=2^4=16
Hence:sum.of odd coefficients of (1+x)^5 is 16
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(x+1)⁵= x⁵+ 2×x+1+1⁵
=x⁵+ 2x+2
=5x+2x+2
To solve this type of questions you have to learn the algebraic expression formula
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