Math, asked by khusboogupta171, 4 days ago

The sum of coefficient in the expansion of (x+1)⁵​

Answers

Answered by NatureDash
0

Answer:

Step-by-step explanation:

In bionomial expansion of (a+b)^n, n is a positive integer the sum of odd coefficients equal 2^n-1

So for (1+x)^5,sum of odd coefficients will be:

2^5-1=2^4=16

Hence:sum.of odd coefficients of (1+x)^5 is 16

Answered by thunderomsai
0

(x+1)⁵= x⁵+ 2×x+1+1⁵

=x⁵+ 2x+2

=5x+2x+2

To solve this type of questions you have to learn the algebraic expression formula

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