Question

the sum of consecutive multiples of 7 is 357. find the smallest multiple

Answer 1

here
first term be - x
common difference - 7
no. of term be - 7
sum of 7 terms be-357
now ,

Sn=n/2{2a+(n-1)d}
357=7/2{2a+(7-1)×7}
51=1/2{2a+42}
102=2a+42
2a=102-42
2a=60
a=30

so., the smallest multiple is 30

Answer 2

Here You Go.........