Question

THE SUM OF CONSECUTIVE TERM IN A.P IS 6AND PRODUCT IS _120 FIND THE THREE NUMBER

Answer 1

Let the no. be a-d, a, a+d

Adding them
3a=6
→a=2

Also (a-d)×a×(a+d)=-120
(a^2-d^2)a=-120
Using a=2
4-d^2=-60
64=d^2
→d=8

So required AP→ -6,2,10