Question

The sum of coordination number and oxidation number of metal m in complex [m(en)2(c2o4)]cl is

Answer 1

let oxidation state of m be 'x'

hence,             x + 1(0) + 2(-2) = 1

therefore,        x = 3             .......(1)

Coming on to C.N.

Both en and C2O4 are didentate ligands

therefore C.N = 2(2) + 1(2)

                       = 6              ............(2)

adding eq (1) and (2) we get

6 + 3

= 9

NOTE : C.N. stands for Coordination No.

Thank you

hope it helps