Question

The sum of coordination number and oxidation number of the metal m in the complex m(en)2(c2o4) cl

Answer 1

Answer:

[M(en)2(C2O4)]Cl Oxidation number of metal = +3 Coordination number of metal = 6 Sum of oxidation number and coordination number = 3 + 6 = 9

Explanation:

Answer 2

let oxidation state of m be 'x'

hence,             x + 1(0) + 2(-2) = 1

therefore,        x = 3             .......(1)

Coming on to C.N.

Both en and C2O4 are didentate ligands

therefore C.N = 2(2) + 1(2)

                       = 6              ............(2)

adding eq (1) and (2) we get

6 + 3

= 9

NOTE : C.N. stands for Coordination No.