The sum of coordination number and oxidation number of the
metal M in the complex [M(en)₂(C₂O₄)]Cl (where en is
ethylenediamine) is: [2015 RS]
(a) 9 (b) 6
(c) 7 (d) 8
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a) 9 is the sum of coordination number and oxidation number
Explanation:
let oxidation state of m be 'x'
hence, x + 1(0) + 2(-2) = 1
therefore, x = 3 .......(1)
Coming on to C.N.
Both en and C2O4 are didentate ligands
therefore C.N = 2(2) + 1(2)
= 6 ............(2)
adding eq (1) and (2) we get
6 + 3
= 9
C.N. stands for Coordination No
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