The sum of denominator and numerator of a fraction is 3 less than twice the denominator. If
each of the numerator and denominator is denominator is decreased by 1, the fraction becomes
1/2. Find the fraction.
Answers
Answered by
38
let the fraction be x / y
then acc. to ques.
x + y + 3= 2y
x = y - 3 ............. (i)
also
x-1/y-1 = y/2y = 1/2
x - 1 =( y-1) / 2
x = ( (y - 1) / 2 ) +1
x = (y +1) / 2
2x = y + 1
2x - y = 1 ............... (ii)
Subtituting the value of (i) in (ii) we have
2 ( y - 3 ) - y =1
2y - 6 -y = 1
y - 6 = 1
y = 7
x = y - 3
x = 7 - 3
x = 4
Therefore the fraction is x / y = 4 / 7
IF IT IS CORRECT MARK BRAINLIEST ✌️
then acc. to ques.
x + y + 3= 2y
x = y - 3 ............. (i)
also
x-1/y-1 = y/2y = 1/2
x - 1 =( y-1) / 2
x = ( (y - 1) / 2 ) +1
x = (y +1) / 2
2x = y + 1
2x - y = 1 ............... (ii)
Subtituting the value of (i) in (ii) we have
2 ( y - 3 ) - y =1
2y - 6 -y = 1
y - 6 = 1
y = 7
x = y - 3
x = 7 - 3
x = 4
Therefore the fraction is x / y = 4 / 7
IF IT IS CORRECT MARK BRAINLIEST ✌️
meenaharsh255:
poor ans
Similar questions