Question

The sum of denominator and numerator of a fraction is 40 if 1 is added to both the numerator and the denominator the fraction becomes 3/4 find the fraction

Answer 1

this will help you for sure
100%
please follow me if it does

Answer 2

☆ANSWER:

Given:

The sum of denominator and numerator of a fraction is 40 if 1 is added to both the numerator and the denominator the fraction becomes 3/4 find the fraction

A.T.Q:

Let the required fraction be $\frac{x}{y}$

Then, we have: $x + y = 40$ [equation (i)]

And, $\frac{x + 1}{y + 1} = \frac{3}{4}$

=>$4(x + 1) = 3(y + 1)$

=> $4x + 4 = 3y + 3$

=> $4x - 3x = - 1$ [equation (ii)]

On multiplying, equation (i) by 3, we get $3x + 3y = 120$ [equation (iii)]

On adding equation (ii) and (iii), we get

$4x - 3y = - 1 \\ \frac{3x + 3y = 120}{7x + 0 = 119}$

So, $x = \frac{119}{7}$

$x = 17$

On substituting $x = 17$ in equation (i), we get:

=> $x + y = 40$

=> $17 + y = 40$

=> $y = 40 - 17$

=> $y = 23$

Now, $\frac{x}{y} = \frac{17}{23} (Ans)$

PLEASE MARK ✨BRAINLIEST✨