Question

The sum of differences of the zeroes of the quadratic polynomial x2 + ax + 45 is equal to 144 then the value of ‘a’ is

Answer 1

Answer:

hi, in this the variable for 'a' is 'p' please check it

hope it helps you

Answer 2

Answer: p=±18

Step-by-step explanation:

Let  α, be the zeroes of the given quadratic polynomial f(x)=x2+px+45

∴α+β=−p,αβ=45

It is given that, (α−β)2=144

⇒(α+β)2–4αβ=144

⇒(–p)2–4×45=144

⇒p2–180=144

⇒p2=144+180

⇒p2=324

⇒p=±324​

∴p=±18