Question

the sum of digit if a two digit number us 10 if 36 is subtracted from the number the digit interchange their places find the number

Answer 1

The sum of digits of a 2 digit number is 10.

let the ones digit=x then tenth digit=10-x

the no is 10[10-x]+x

when the digits interchange their position the no will be 10x+[10-x]

The digits of the number interchange their places, when 36 is subtracted from the number.

so 10x+[10-x]=10[10-x]+x-36

or 10x+10-x=100-10x+x-36

or 18x=54

or x=3

so the two digit number=10[10-x]+x=10[10-3]+3=73