The sum of digit of a 2 digit number is 10. If 36 is added to the number the digits are reversed what is the number
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let required number be (10x+y)
x+y=10 ----------(1)
(10x+y)+36=10y+x
by solving,
x-y=-4. -------------(2)
comparing first and second equation,
x=3 then y=7
then number is 37.
x+y=10 ----------(1)
(10x+y)+36=10y+x
by solving,
x-y=-4. -------------(2)
comparing first and second equation,
x=3 then y=7
then number is 37.
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