the sum of digit of a 2- digit number is 11 . if the number obtained by reversing the digit is 9 less than the original number , find the number
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8
x+y=11
10x+y-9=10y+x
9x-9y=9
x-y=1
x+y=11
2x=12
x=6
y=5
The number is 65
10x+y-9=10y+x
9x-9y=9
x-y=1
x+y=11
2x=12
x=6
y=5
The number is 65
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3
The origanl no is 65..
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