The sum of digit of a 2-digit number is 7 .if 27 is added to the number ,the digit interchange their places .find the number
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Let the digit in unit's place be "y" and the digit in ten's place be "x"
Then the two digit no: is 10x + y
A.T.Q.,
x + y = 7 -----> (1)
also,
When digits are interchanged the no: is --> 10y +x
10x + y + 27 = 10y + x
10x - x + y - 10y = -27
9x - 9y = -27
9(x- y) = -27
x - y = -3 ----> (2)
--------------------------------------------------
Adding (1) and (2) ,
x + y = 7
x - y = -3
--------------------
2x = 4
x = 2
x + y = 7
2 + y = 7
y = 7 -2
y = 5
--------------------------------------------------
10x + y ---> 10(2) + 5 = 25
The no: is 25
Let the digit in unit's place be "y" and the digit in ten's place be "x"
Then the two digit no: is 10x + y
A.T.Q.,
x + y = 7 -----> (1)
also,
When digits are interchanged the no: is --> 10y +x
10x + y + 27 = 10y + x
10x - x + y - 10y = -27
9x - 9y = -27
9(x- y) = -27
x - y = -3 ----> (2)
--------------------------------------------------
Adding (1) and (2) ,
x + y = 7
x - y = -3
--------------------
2x = 4
x = 2
x + y = 7
2 + y = 7
y = 7 -2
y = 5
--------------------------------------------------
10x + y ---> 10(2) + 5 = 25
The no: is 25
ŽKħąń:
the question is so easy why you solve it so long ?
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