Question

The sum of digit of a 2-digit number is 8. the number obtained by interchanging the digit exceeds the given number by 18. Find the given numbers

Answer 1

Let the tens digit be x and units digit be y
x+y=8.....number is 10x+y
If digits are interchanged number becomes 10y+x......
Acc to given information 10y+x=10x+y+18
Solve the equations.. And get ans

Answer 2

let,

the ones digit be x

tens digit=8-x

two digit number=

10(8-x) +x=80-10x+x=80-9x

after interchanging the no :

10x+(8-x) =10x+8-x=9x+8

A.T.Q,

9x+8-(80-9x) =18

9x+8-80+9x=18

18x-72=18

18x=18+72

18x=90

x=90/18

x=5

therefore,

10(8-x) +8

10(8-5)+8

35

9x+8

9*5+8

53