The sum of digit of a 2 digit number is 9 if 27 is subtracted from the number the digit are reversed find the number
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1
Answer:
63
Step-by-step explanation:
let the the number be x
and another no be y
Atq
the sum of the digit of a 2 digit no is 9
=>x+y=9..................(i)
and
its also given,
10y + x - 27 = 10x + y
=> 10y - y + x - 10x = 27
=> 9y - 9x = 27
=> 9 ( y - x ) = 27
=> y - x = 3...............(ii)
Now, By adding eq. (i) and (ii), we get
x + y = 9
- x + y = 3
2y = 12
( y = 6 )
Now, put the value of y = 6 in eq. (i)
x + y = 9
x + 6 = 9
x = 9 - 6
( x = 3 )
Then, Number = 10y + x
= 10 ( 6 ) + 3
= 60 + 3
= 63
Hence, The required number is 63.
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