Question

The sum of digit of a digit no. is 7. if the digit ax reveresed,the new no. increased by 3 equal 4 times the original no. find the no.the ans in brainly app

Answer 1

Given :

• The sum of digit of a digit no. is 7.

• The digit ax reveresed,the new no. increased by 3 equal 4 times the original no.

To find :

• The original number =?

Step-by-step explanation :

Let, the ones digit of the two digits number be, x

Then, the tens digit of two digit number is, 7 - x.

So, the number is, 10(7 - x + x) = 70 - 9x.

After reversing the digits the number will be, 10x(7 - x) = 9x + 7

According to the question,

➮ 70 - 9x = 4(9x + 7) - 3

➮ 70 - 9x = 36x + 28 - 3

➮ 45x = 70 + 28 - 3

➮ 45x = 45

➮ x = 45/45

➮ x = 1.

Hence,

Once, digit, x = 1

Ten's digit, 7 - x = 7 - 1 = 6

Therefore, the original number,

10 × 1 + 6 = 16.

Answer 2

Answer:

The original number = 16.

Given :

➛ The sum of digit of a digit no. is 7.

➛The digit is reveresed,the new no. increased by 3 equal 4 times the original no.

To find :

The original number.

Solution:

we are given,

➛ The sum of digit of a digit no. is 7.

➛The digit is reveresed,the new no. increased by 3 equal 4 times the original no.

Let, the ones digit of the two digits number be, m

Then, the tens digit of two digit number is, 7 - m.

So, the number is, 10(7 - m + m) = 70 - 9m.

➨After reversing the digits the number will be, 10m(7 - m) = 9m + 7

➦ 70 - 9m = 4(9m + 7) - 3

➦ 70 - 9m = 36m + 28 - 3

➦ 45m = 70 + 28 - 3

➦ 45m = 45

➦ m = 45/45

➦ m = 1.

Hence,

Once, digit, m = 1

Ten's digit, 7 - m = 7 - 1 = 6

Therefore, the original number = 16.