Question

the sum of digit of a two digit no is 15. if the no formed by revering the digits is less than the original no by 27. find the original no.​

Answer 1

Answer:

Step-by-step explanation:

First digit= (ones place) x-9

second digit= (tens place) x

the original number= 10x+(9-x)= 15

After interchanging= 10(9-x)+ x

10(9-x)+ x+27= 10x+(9-x)

90+27= 10x+9-x

117-9= 9x

108=9x

108/9= x

12 = x

to find the digts, 12/ 2(due to x being repeated twice)

the second digit= 6

first digit= 12- 3= 9

therefore the number is 96

Hope this answer helps!

Please mark my answer as brainliest!!