The sum of digit of a two digit number is 10.when the digit are reversed,the number decreased by 54.find the changed number.
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Answered by
1
82 is the answer of questions
skrmldtpamz6v:
procedure
just write the eq
write the equation only
x+Y=10
10x+y=10y+x-54
10x+y is the answer
x and y are ones and tenth place digits
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Answered by
3
Hi
Let the two digits number be 10x+y.
By the problem,
x+y = 10...(1)
Also,
10y+x =10x +y +54
=>9x - 9y = - 54
=> x - y = - 6...(2)
Adding (1) and (2) we get
2x = 4
=>x =2
Thus y =10-2 = 8
Thus the required two digit number
=10(2)+8
28 (ans)
Hope this helps.
Let the two digits number be 10x+y.
By the problem,
x+y = 10...(1)
Also,
10y+x =10x +y +54
=>9x - 9y = - 54
=> x - y = - 6...(2)
Adding (1) and (2) we get
2x = 4
=>x =2
Thus y =10-2 = 8
Thus the required two digit number
=10(2)+8
28 (ans)
Hope this helps.
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