Question

the sum of digit of a two digit number is 11 when the digit are interchanged the new number formed is less than the original number by 27 find the original numbers​

Answer 1

Answer:

Let the 2 digit number as(10a+b)

Number obtain by reversing the digit=(10b+a)

Given,

( a+b=11)~equation-1

also,

=(10a+b)-(10b+a)=9

=10a+b-10b-a=9

=9a-9b=9

=9(a-b)=9

=(a-b)=9–9

=a-b=1

=a+b+a-b=11+1

=2a=12

=a=6

Putting the value of a in equation 1, we get

=6+b=11

=b=11–6

=b=5

Original number=10×6+5=60+5=65

So the require number is 65