The sum of digit of a two digit number is 15 find the number formed by reversing the digit is less than the original number 27.Solve in one variable
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Answer:
96
Step-by-step explanation:
let tens digit of the original number be x
so original number,
10 (x) + (15-x)
reversing digit mean
10(15-x)+x
[10(x) + (15-x)]-[10(15-x)+x]= 27
or 10x+15x-150+10x-x= 27
or 10x+10x+15-150-x-x= 27
or 20x-135-2x= 27
or 18x-135= 27
or 18x= 27+135
or 18x= 162
or x= 162/18
or x= 9
original number= 10(x) + (15-x)
= 10(9) + (15-9)
= 90+6
= 96
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