Question

the sum of digit of a two digit number is 17 the new number formed by reversing the digits is greater than the original number by 9 find the original number

Answer 1

$\bf\huge\color{blue}\mathbb{HEYA\:MATE\: :)}\\\bf\color{violet}{Here\:is\:your\:answer}$

Let the digit on unit's place be x
and in ten's place be y.

So,the number is (10x + y)
and Reversed no. is (10y + x)

A.T.Q,
x + y = 17 _____(1)
and 10y + x - (10x + y) = 9
=> 9y - 9x = 9
=> 9(-x + y) = 9

=> -x + y = 1_____(2)

Adding equations (1) and (2) we get,
2y = 18 [-x and +x cancels out]

=> $\bf\huge\color{red}{y=9}$

Substituting value of y in equation(2)* we get,
-x + 9 = 1
=> -x = -8

=> $\bf\huge\color{red}{x=8}$

Hence no. is 10x + y.

= 10(8)+9
= 80+9
=89

Hope this helps!!!
plzz mark as BRAINLIEST

Answer 2

❤❤Here is your answer ✌ ✌

$\huge\underline {\red {\bold {Answer}}}$
Let the digit on unit's place be x 
and in ten's place be y.

So,the number is (10x + y)
and Reversed no. is (10y + x)

A.T.Q, 
x + y = 17 _____(1)
and 10y + x - (10x + y) = 9
=> 9y - 9x = 9
=> 9(-x + y) = 9

=> -x + y = 1_____(2)

Adding equations (1) and (2) we get,
2y = 18 [-x and +x cancels out]

=> y=9 

Substituting value of y in equation(2)* we get,
-x + 9 = 1
=> -x = -8

=> x=8 

Hence no. is 10x + y.

= 10(8)+9
= 80+9
=89

Hope this helps.