Question

the sum of digit of a two digit number is 8. on adding 18 to the Number,its digits are reversed.find the Number.

Answer 1

let the number be x
therefore,x+18=8
x= -10

Answer 2

Here is the solution my friend :)

Let the digits at tens place be x and
Unit place be y

Therefore, the number =10x+y
A/Q
X+y = 8 ---------------eqn 1
10x+y+18= 10y+x
( as digits are reversed)
Solving this we get
10x-x+y-10y =-18
9x-9y= - 18
9(x-y)= - 18
X-y = - 18/9
X-y = - 2 - - - - - - - - - - eqn 2

Solving both equations
X+y =8
X-y=-2

We get
2x = 6
X = 3
Now putting the value of x in eqn 1 ( u can put in any eqn)

X+y=8
3+y =8
Y =5

Therefore the required number is 10x+y
= 35 is the answer

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